strpbrk
char * strpbrk ( const char * string1, const char * string2 ); | string.h |
cplusplus.com |
Scan string for specified characters.
Scans string1 character by character, returning a pointer to
the first character that matches with any of the characters in string2.
The search does not includes the terminating null-characters.
Parameters.
Return Value.
A pointer to the first appearance in string1 of a character specified in string2.
If none of the characters specified in string2 exists in string1, a NULL
pointer is returned.
Portability.
Defined in ANSI-C.
ANSI-C++ standard specifies two different
declarations for this function instead of the one included in ANSI-C:
const char * strpbrk ( const char * string1, const char * string2 );
char * strpbrk ( char * string1, const char * string2 );
Both have the same behavior as the original declaration.
Example.
/* strpbrk example */
#include <stdio.h>
#include <string.h>
main ()
{
char str[] = "This is a sample string";
char key[] = "aeiou";
char * pch;
printf ("Vowels in '%s': ",str);
pch = strpbrk (str, key);
while (pch != NULL)
{
printf ("%c " , *pch);
pch = strpbrk (pch+1,key);
}
printf ("\n");
return 0;
}
Output:
Vowels in 'This is a sample string': i i a a e i
See also.
strcspn,
strchr,
strrchr