| strpbrk char * strpbrk ( const char * string1, const char * string2 ); | string.h | 
| cplusplus.com | 
 Scan string for specified characters.
 
Scans string1 character by character, returning a pointer to
the first character that matches with any of the characters in string2.
 
The search does not includes the terminating null-characters.
Parameters.
 Return Value.
 
A pointer to the first appearance in string1 of a character specified in string2.
 
If none of the characters specified in string2 exists in string1, a NULL
pointer is returned.
 Portability.
 
Defined in ANSI-C.
 
ANSI-C++ standard specifies two different
declarations for this function instead of the one included in ANSI-C:
const char * strpbrk ( const char * string1, const char * string2 );
      char * strpbrk (       char * string1, const char * string2 );
 
Both have the same behavior as the original declaration.
 Example.
/* strpbrk example */
#include <stdio.h>
#include <string.h>
main ()
{
  char str[] = "This is a sample string";
  char key[] = "aeiou";
  char * pch;
  printf ("Vowels in '%s': ",str);
  pch = strpbrk (str, key);
  while (pch != NULL)
  {
    printf ("%c " , *pch);
    pch = strpbrk (pch+1,key);
  }
  printf ("\n");
  return 0;
}
Output:
Vowels in 'This is a sample string': i i a a e i
 See also.
 
strcspn,
strchr,
strrchr